(2x-1)^2+(x+3)^2-5(x+7)(x-7)

2 min read Jun 16, 2024
(2x-1)^2+(x+3)^2-5(x+7)(x-7)

Simplifying the Expression: (2x-1)^2 + (x+3)^2 - 5(x+7)(x-7)

This article will guide you through the process of simplifying the given algebraic expression: (2x-1)^2 + (x+3)^2 - 5(x+7)(x-7).

Expanding the Squares

First, we need to expand the squares using the formula (a+b)^2 = a^2 + 2ab + b^2:

  • (2x-1)^2 = (2x)^2 + 2(2x)(-1) + (-1)^2 = 4x^2 - 4x + 1
  • (x+3)^2 = x^2 + 2(x)(3) + 3^2 = x^2 + 6x + 9

Expanding the Product

Next, we expand the product using the difference of squares formula (a+b)(a-b) = a^2 - b^2:

  • 5(x+7)(x-7) = 5(x^2 - 7^2) = 5(x^2 - 49)

Combining the Terms

Now, we can substitute the expanded terms back into the original expression and combine like terms:

(2x-1)^2 + (x+3)^2 - 5(x+7)(x-7) = (4x^2 - 4x + 1) + (x^2 + 6x + 9) - 5(x^2 - 49)

= 4x^2 - 4x + 1 + x^2 + 6x + 9 - 5x^2 + 245

= (4x^2 + x^2 - 5x^2) + (-4x + 6x) + (1 + 9 + 245)

= 2x + 255

Final Result

Therefore, the simplified form of the expression (2x-1)^2 + (x+3)^2 - 5(x+7)(x-7) is 2x + 255.

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